Question

( sin theta + I cos theta)^ 6 = ?

Answer 1

Answer:

$(sinx+cosx)^{6} =sin^{6}x+6sin^{5}x.cosx+15sin^{4}.cos^{2}x+20sin^{3}x.cos^{3}x+15sin^{2}.cos^{4}x+6sinx.cos^{5}x+cos^{6}x$

Step-by-step explanation:

$(A + B)^{6} = A^{6} + 6A^{5}B + 15A^{4}B^{2} + 20A^{3}B^{3} + 15A^{2}B^{4} + 6AB^{5} + B^{6}$

This is the formula we need to use here.So....

$(sinx+cosx)^{6} =sin^{6}x+6sin^{5}x.cosx+15sin^{4}.cos^{2}x+20sin^{3}x.cos^{3}x+15sin^{2}.cos^{4}x+6sinx.cos^{5}x+cos^{6}x$

Hope helps u......