sin theta is equal to 3 by 7 find secant theta and Cot theta
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Let's consider a right ΔABC with ∠B = 90° and ∅=∠A.
Now sin A = BC÷AC
So, BC=3units and AC=7units.
By Pythagoras theorem, AB = √40
So sec∅ = 7/√40
And cot∅ = √40/3
Now sin A = BC÷AC
So, BC=3units and AC=7units.
By Pythagoras theorem, AB = √40
So sec∅ = 7/√40
And cot∅ = √40/3
harshith29:
sis write in paper
I scribbled on paper. Appreciate that I patiently sat and typed the whole thing
sorry
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