sin theta minus 2 Sin cube theta divided by 2 cos cube theta minus cos theta equal to tan theta
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Answer:
LHS = sin∅-2sin³∅
2cos³∅-cos∅
=> sin∅(1-2sin²∅)
cos∅(2cos²∅-1)
=> sin∅(cos2∅)
cos∅(cos2∅)
(both are the formulas of cos2∅)
=> sin∅/cos∅
=> tan∅ = RHS
Hence proved
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