sin theta minus 2 Sin cube theta upon 2 cos cube theta minus cos theta
Answers
Answered by
65
hello users ......
Question:-
(sinθ - 2sin³θ ) / (2cos³ θ -cos θ) =?
solution:-
we know that:
cos 2θ = (2cos² θ - 1 )= (1 - 2sin² θ)
here,
(sinθ - 2sin³θ ) / (2cos³ θ -cos θ)
= sinθ ( 1 - 2sin² θ) / cos θ (2cos² θ - 1 )
= sin θ ×cos 2θ / cos θ × cos 2θ
= tan θ Answer
✡✡ hope it helps ✡✡
Question:-
(sinθ - 2sin³θ ) / (2cos³ θ -cos θ) =?
solution:-
we know that:
cos 2θ = (2cos² θ - 1 )= (1 - 2sin² θ)
here,
(sinθ - 2sin³θ ) / (2cos³ θ -cos θ)
= sinθ ( 1 - 2sin² θ) / cos θ (2cos² θ - 1 )
= sin θ ×cos 2θ / cos θ × cos 2θ
= tan θ Answer
✡✡ hope it helps ✡✡
Answered by
65
Answer is in attachment.
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