Question

sin theta minus 2 Sin cube theta upon 2 cos cube theta minus cos theta

Answer 1

hello users ......

Question:-
(sinθ - 2sin³θ ) / (2cos³ θ -cos θ) =?

solution:-
we know that:
cos 2θ = (2cos² θ - 1 )= (1 - 2sin² θ)

here,
(sinθ - 2sin³θ ) / (2cos³ θ -cos θ)

= sinθ ( 1 - 2sin² θ) / cos θ (2cos² θ - 1 )

= sin θ ×cos 2θ / cos θ × cos 2θ

= tan θ Answer

✡✡ hope it helps ✡✡

Answer 2

Answer is in attachment.