Math, asked by sushilamajhi9906, 7 months ago

sin theta /sec theta +tan theta -1 +cos theta /cosec theta +cot theta-​

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Answered by yahyadkazi
0

Answer:

Step-by-step explanation:

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`(cos(90^0-theta)sec(90^0-theta)tantheta)/(cos ... `(sec theta cosec (90^(@)-theta)-tan theta cot (90^(@)-theta)+sin^(2)55^@+sin^(2)35 .

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