sin theta +sin^2 theta =1 then cos^2 theta +cos^4 theta is equal to
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▪︎Given:-
- Sinθ +sin²θ = 1
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▪︎To Find:-
- cos²θ + cos⁴θ = ?
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▪︎T-Ratios Used:-
- sin²θ + cos²θ = 1
Or
- sin²θ = 1 - cos²θ
Or
- cos²θ = 1 - sin²θ
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▪︎Solution:-
➢ As given in question;
Sinθ + sin²θ = 1 ---------- eq.1
➟ Sinθ = 1 - sin²θ
➢ As we know, 1 - sin²θ = cos²θ
Putting the value in equation
➟ Sinθ = cos²θ ------- eq.2
➢ By squaring both sides of eq.2 ,
➟ (Sinθ)² = (cos²θ)²
➟ Sin²θ = cos⁴θ -------- eq.3
➢ Putting value of eq. 2 and 3 in eq.1
Sinθ + sin²θ = 1
➟cos²θ + cos⁴θ = 1
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▪︎Answer:-
☆ cos²θ + cos⁴θ = 1
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