Math, asked by deepanjalipande67, 1 year ago

sin(π+theta)sin(π-theta)cosec^2theta = ?​

Answers

Answered by ihrishi
17

Answer:

sin( \pi +  \theta)sin( \pi  -   \theta) {cosec}^{2} \theta \\  =  - sin\theta \times sin\theta \times {cosec}^{2} \theta \\  =  -  {sin}^{2} \theta  \times {cosec}^{2} \theta \\  = -  {sin}^{2} \theta  \times \frac{1}{{sin}^{2} \theta}  \:  \\  =  - 1

Answered by nanda1729
10

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