sin theta + sin² theta =0. find sin² theta +sin⁴ theta
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5
zero
after the steps like squaring on both sides also the lhs remain the same
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3
Answer: 0
Step-by-step explanation:
sinθ + sin²θ = 0 (given) ------- (eq 1)
sin²θ + sin⁴θ
sinθ × sinθ + sin²θ × sin²θ
(sinθ + sin²θ)(sinθ + sin²θ)
0 × 0 ------ (from 1)
= 0
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