Question

sin theta + sin² theta =0. find sin² theta +sin⁴ theta​

Answer 1

zero

after the steps like squaring on both sides also the lhs remain the same

Answer 2

Answer: 0

Step-by-step explanation:

sinθ + sin²θ = 0 (given) ------- (eq 1)

sin²θ + sin⁴θ

sinθ × sinθ + sin²θ × sin²θ

(sinθ + sin²θ)(sinθ + sin²θ)

0 × 0 ------ (from 1)

= 0