sin theta× tan theta/1-cos theta= 1+sec theta
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Step-by-step explanation:
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Step-by-step explanation:
i am using A in place of theta
sinAtanA/(1-cosA)
rationalising with (1+cosA)
= sinAtanA(1+cosA)/(1-cos^2A)
= sinAtanA(1+cosA)/sin^2A
= tanA(1+cosA)/sinA
= (sinA/cosA)*(1+cosA)/sinA
= (1+cosA)/cosA
= 1/cosA + 1
= 1 + secA
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