Math, asked by vidhyasridhar08, 9 months ago

sin theta× tan theta/1-cos theta= 1+sec theta

Answers

Answered by aaryanrichu

0

Step-by-step explanation:

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Answered by amitsnh

1

Step-by-step explanation:

i am using A in place of theta

sinAtanA/(1-cosA)

rationalising with (1+cosA)

= sinAtanA(1+cosA)/(1-cos^2A)

= sinAtanA(1+cosA)/sin^2A

= tanA(1+cosA)/sinA

= (sinA/cosA)*(1+cosA)/sinA

= (1+cosA)/cosA

= 1/cosA + 1

= 1 + secA

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