sin theta=thera if theta is specifically less than: (a)15°(b)10° (0)5° (d)1 radian
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Answer:
(1+cosA)(1-cosA=(1)sq=(cosA)sq
[by (a+b)(a-b)=(a)sq-(b)sq]
Explanation:
=hence (1-cosAsq)
=sinAsq
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