Question

sin theta upon 1 + cos theta + 1 + cos theta upon sin theta = 2 cosec theta

Answer 1

Hey mate here is ur answer
HOPE THIS ANSWER WILL HELP U
PLEASE MARK IT BRAINLIEST ❤️

Answer 2

Formulas to use:

sin θ = 1/cosec θ

sin²θ + cos²θ = 1

Step-by-step explanation:

Given :

L.H.S

sin θ / ( 1 + cos  θ ) + ( 1 + cos  θ ) / sin  θ

⇒ ( sin² θ + ( 1 + cos θ )² ) / ( sin θ ( 1 + cos θ ) )

⇒ ( sin² θ + 1 + cos²θ + 2 cos θ ) / ( sin θ ( 1 + cos θ )

⇒ ( 1 + 1 + 2 cos θ ) / ( sin θ ( 1 + cos θ ) )

⇒ ( 2 + 2 cos θ ) / ( sin θ ( 1 + cos θ ) )

⇒ 2 ( 1 + cos θ )/ ( 1 + cos θ ) sin θ

⇒ 2/sin θ

⇒ 2 cosec θ

L.H.S = R.H.S

[ Proved ]