Question

sin theta upon 1 + cos theta equals to 1 minus sin theta upon sin theta equals to sin cos theta upon 1 minus cos theta answer​

Answer 1

Answer:

$\frac{sin\theta}{1+cos\theta}=\frac{1-cos\theta}{sin\theta}$

Step-by-step explanation:

I think your question may be

"Prove that : $\frac{sin\theta}{1+cos\theta}=\frac{1-cos\theta}{sin\theta}$"

$\frac{sin\theta}{1+cos\theta}$

$=\frac{sin\theta}{1+cos\theta}*\frac{1-cos\theta}{1-cos\theta}$ (multiplying both Nr. and Dr. by $1-cos\theta$)

$=\frac{sin\theta(1-cos\theta)}{1^2-cos^2\theta}$

$=\frac{sin\theta(1-cos\theta)}{1-cos^2\theta}$

$=\frac{sin\theta(1-cos\theta)}{sin^2\theta}$

$=\frac{1-cos\theta}{sin\theta}$

Answer 2

Step-by-step explanation:

this the answer of this question