sin theta upon 1 minus Cos = cosec theta + cot theta
Answers
Answered by
0
Taking R•H•S
1/sin theta + cos theta/sin theta
:- (1+ cos theta )/sin theta
Now taking both R•H•S & L•H•S
sin theta/1-cos theta=(1+cos theta)/sin theta
:- sin^2 theta=1^2-cos^2 theta
:- sin^2 theta+ cos^2 theta = 1
:- 1=1
1/sin theta + cos theta/sin theta
:- (1+ cos theta )/sin theta
Now taking both R•H•S & L•H•S
sin theta/1-cos theta=(1+cos theta)/sin theta
:- sin^2 theta=1^2-cos^2 theta
:- sin^2 theta+ cos^2 theta = 1
:- 1=1
Similar questions
Science,
7 months ago
Math,
7 months ago
English,
1 year ago
Math,
1 year ago
India Languages,
1 year ago