sin theta upon 1 minus cos theta is equal to cosec theta + cot theta is equal to prove that
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We take α at the place of theta...
Sinα /1-cosα =cosecα+cotα
Ok
(Sinα/1-cosα) LHS
multiply by conjugate IE. 1+ cosα both numerator and denominator
(Sinα /1-cosα)* 1+ cos α/ 1+ cosα
Sin.α* 1+cosα/1-cos^2α
Sinα +cosα•sinα/sin.^2α
Separated
=Sinα/sin.^2α + sinα•cosα/sin.^2α
=1/sin.α +cosα/sin.α
Cosecα + cotα
RHS...
Sinα /1-cosα =cosecα+cotα
Ok
(Sinα/1-cosα) LHS
multiply by conjugate IE. 1+ cosα both numerator and denominator
(Sinα /1-cosα)* 1+ cos α/ 1+ cosα
Sin.α* 1+cosα/1-cos^2α
Sinα +cosα•sinα/sin.^2α
Separated
=Sinα/sin.^2α + sinα•cosα/sin.^2α
=1/sin.α +cosα/sin.α
Cosecα + cotα
RHS...
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