sin theta upon 1 minus cos theta +tan theta upon 1 + cos theta is equal to sec theta cosec theta + cot theta
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Answered by
10
Answer:
Okay, very easy.
sinA(1+CosA) + tanA(1-cosA)/ 1-Cos^2A
=. SinA+SinAcosA + tanA-SinA/Sin^2A
= SinACosA+TanA/Sin^2A
= SinACosA/Sin^2A + TanA/Sin^2A
=CosA/SinA + 1/SinACosA
= CotA + secACosecA.
Thank me later
enoshvsavalam7:
Thanks
Answered by
1
Answer:
hence proved
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