Question

Sin theta xisec theta relation

Answer 1

hey mate
here is your answer
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$\sin(\theta) = \frac{perpandicular} {hypotenuse}$

$\cosec(\theta) = \frac{hypotenuse}{perpandiclur}$
so,

$\sin( \theta) = \frac{1}{ \cosec(\theta) }$
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Answer 2

hi

here is your answer.....

sin (theta)= 1/ cosec (theta)