sin thetha = 1/2. Find other ratio
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Sin¢ = 1/2 = P/H
P = 1 , H = 2
By Pythagoras theroem ,
( H )² = (B)² + (P )²
( B )² = (H)² - (P )²
( B )² = (2)² - (1)²
B = √3.
Therefore,
Sin¢ = P / H = 1/2
Cos ¢ = B/H = √3/2
Tan¢ = P/B = 1/√3
Cosec¢ = H/P = 2/1
Sec ¢ = H/B = 2/ √3
And,
Cot ¢ = B/P = √3/1
P = 1 , H = 2
By Pythagoras theroem ,
( H )² = (B)² + (P )²
( B )² = (H)² - (P )²
( B )² = (2)² - (1)²
B = √3.
Therefore,
Sin¢ = P / H = 1/2
Cos ¢ = B/H = √3/2
Tan¢ = P/B = 1/√3
Cosec¢ = H/P = 2/1
Sec ¢ = H/B = 2/ √3
And,
Cot ¢ = B/P = √3/1
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