sin thita = 3/5
then find the
4
Value of cos thita
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Answer:
sin theta = 3/5
sin theta = perpendicular/hypotenuse
(hypotenuse)² = (perpendicular)²+(base)²
5² = 3²+b²
b² = 5²-3²
b = √25-9
b = 4
cos theta = base/hypotenuse = 4/5
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Answer:
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