sin thita + cos thita = √2 cos thita then prove that cos thita - sin thita = √2 sin thita
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Step-by-step explanation:
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Step-by-step explanation:
> cos θ + sin θ = √2 cos θ
--> sin θ = √2 cos θ - cos θ
=> sin θ = ( √2 - 1 ) cos θ
=> [ sin θ / ( √2 - 1 ) ] = cos θ
=> [ sin θ ( √2 + 1 ) / ( 2 - 1 ) ] = cos θ
--> We rationalized the denominator in the 2nd step
=> [ √2 sin θ + sin θ ] = cos θ
=> cos θ - sin θ = √2 sin θ
√\___________Anushka❤❤
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