Question

sin thita -cos thita= root 2 ,class 11th shivalal book chapter 4 (e) 2 and don't spam will I report you ...​

Answer 1

Answer:

Step-by-step explanation:

> cos θ + sin θ = √2 cos θ

--> sin θ = √2 cos θ - cos θ

=> sin θ = ( √2 - 1 ) cos θ

=> [ sin θ / ( √2 - 1 ) ] = cos θ

=> [ sin θ ( √2 + 1 ) / ( 2 - 1 ) ] = cos θ

--> We rationalized the denominator in the 2nd step

=> [ √2 sin θ + sin θ ] = cos θ

=> cos θ - sin θ = √2 sin θ

√\___________Arun