Question

Sin thita/ cosec thita-1 + cos thita/ 1+ sec thita = sin thita×cos thita/sin thita - cos thita

Answer 1

Take LHS Side

SinQ/CosecQ-1+ cosQ/1+SecQ

SinQ/(1/sinQ)-1+CosQ/(1 +1/cos Q)

Sin^2Q-1+Cos^2Q/(CosQ+1)

- Cos^2Q+Cos^2Q/(cos Q+1)
Cos^2Q[-1+1/(cos Q+1)]

Cos^2Q[-cos Q-1+1]/(cos Q+1)

cos^3Q/(CosQ +1)