Sin thita = m2 - n2 / m2+ n2 find ten thita
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sin thita=m2-n2/m2+n2 = perpendicular/ hypotenus
By Pythagoras theorm
A2+B2=C2
(m2-n2)2 + (x)2 = (m2+n2)2
calculate x
By calculation we get x=2mn
cos Thita = 2mn/m2+n2
tan= sin/cos = m2-n2/2mn
By Pythagoras theorm
A2+B2=C2
(m2-n2)2 + (x)2 = (m2+n2)2
calculate x
By calculation we get x=2mn
cos Thita = 2mn/m2+n2
tan= sin/cos = m2-n2/2mn
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