Question

sin thita + sin ^2 thita =1, show that cos ^2 thita+ cos ^4 thita =1
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Answer 1

Answer:

sinθ + sin²θ = 1

sinθ = 1 - sin²θ

sinθ = cos²θ ---------- ( i )

[ • As sin²θ + cos²θ = 1

So , sin²θ = 1 - cos²θ ]

sinθ = cos²θ

( sinθ )² = ( cos²θ )². (squaring on both side)

sin²θ = cos⁴θ

1 - cos²θ = cos⁴θ

cos⁴θ + cos²θ = 1

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Answer 2

Step-by-step explanation:

sin thita + sin ^2thita=1

Sin thita =1- sin^2thita

Sin thita =cos^2thita

Then,LHS=cos^2thita + cos^4 thita

=sin thita +( cos^2thita)^2

=sin thita + sin^2thita

=1 (given)