sin tita =7/5 then find the value of cos tita.
dhruvsh:
this isn't possible
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heya!!!
We know that. Sin² ( x ) + Cos ² ( x ) = 1
Cos ² ( x ) = 1 - Sin² ( x )
Cos ( x ) = √ { 1 - Sin² ( x ) }
Sin ( x ) = 7 / 5
Sin² ( x ) = 49 / 25
=>
Cos ( x ) = √ { 1 - 49 / 25 }
Cos ( x ) = √ ( -24 / 25 )
Cos ( x ) = √( -24 ) / 5
Cos ( x ) = √24 i / 5
Where i is iota i = √ -1
Have a great future ahead.
We know that. Sin² ( x ) + Cos ² ( x ) = 1
Cos ² ( x ) = 1 - Sin² ( x )
Cos ( x ) = √ { 1 - Sin² ( x ) }
Sin ( x ) = 7 / 5
Sin² ( x ) = 49 / 25
=>
Cos ( x ) = √ { 1 - 49 / 25 }
Cos ( x ) = √ ( -24 / 25 )
Cos ( x ) = √( -24 ) / 5
Cos ( x ) = √24 i / 5
Where i is iota i = √ -1
Have a great future ahead.
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