Question

sin tita .cos(90° - tita) + cos tita.sin(90° - tita ) a) sin 90° b) cos 90° c) 2 d) 0 ​

Answer 1

Answer:

sin 90

Step-by-step explanation:

Let theta  be A

then-

sin A . cos(90-A) + cos A .  sin(90-A)

sin A . sin A + cos A . cos A                [ sin(90-A) = cos A & cos(90-A) = sin A]

$sin^{2}A$ + $cos^{2} A$

=> 1 = sin 90                                            [ sin 90=1]

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