Question

sin tita/cosec tita + cos tita/sec tita =1​

Answer 1

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1 = R.H.S (RIGHT HAND) SIDE = L.H.S (LEFT HAND SIDE

QUESTION:-

$prove \: that \: \frac{ \sin(θ) }{ \csc(θ) } + \frac{ \cos(θ) }{ \sec(θ) } = 1$

Step-by-step explanation:

let's solve L.H.S to make R.H.S:

$\frac{ \sin( θ  ) }{ \csc( θ ) } + \frac{ \cos( θ ) }{ \sec( θ ) }$

●we know cosec θ = 1 / sin θ & sec θ = 1/cos θ

so ,

• sinθ×sinθ + cosθ × cosθ
• sin²θ + cos²θ

→ and we know that sin²θ + cos²θ = 1

• 1 = R.H.S

Hence proved...

Answer 2

Answer:

1 = R.H.S (RIGHT HAND) SIDE = L.H.S (LEFT HAND SIDE

QUESTION:-

prove \: that \: \frac{ \sin(θ) }{ \csc(θ) } + \frac{ \cos(θ) }{ \sec(θ) } = 1provethat

csc(θ)

sin(θ)

+

sec(θ)

cos(θ)

=1

Step-by-step explanation:

let's solve L.H.S to make R.H.S:

\frac{ \sin( θ ) }{ \csc( θ ) } + \frac{ \cos( θ ) }{ \sec( θ ) }

csc( θ )

sin( θ )

+

sec( θ )

cos( θ )

●we know cosec θ = 1 / sin θ & sec θ = 1/cos θ

so ,

sinθ×sinθ + cosθ × cosθ

sin²θ + cos²θ

→ and we know that sin²θ + cos²θ = 1

1 = R.H.S

Hence proved...