sin to the power of 4theta + cos to the power of 4theta=1-2sin square theta cos square theta
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If sin
4
θ+cos
4
θ=1−
2
1
f(θ) then f(
4
π
)=
MEDIUM
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ANSWER
From above sin
4
θ+cos
4
θ=1−
2
f(θ)
f(θ)=(1−sin
4
θ−cos
4
θ)2
f(
4
π
)=(1−sin
4
4
π
+cos
4
4
π
).2
=
⎝
⎛
1−(
2
1
)
4
−(
2
1
)
4
⎠
⎞
2
=(1−
4
1
−
4
1
)×2
=(1−
2
1
)×2=
2
1
×2
f(θ)=1
I Think So It Will Help U !!!
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