Math, asked by rudrakshtiwari420, 6 months ago

sin x/ 1- cosx + tanx /1+ cos x = sec x. cosec. x + cot x​

Answers

Answered by georgebaite8022
4

Answer:

Sinx/(1-Cosx) +Tanx/(1+Cosx)

Step-by-step explanation:

LHS=Sinx/(1-Cosx) +Tanx/(1+Cosx)=[{Sinx.(1+Cosx)}/{(1-Cosx)(1+Cosx)}] +[{Tanx.(1-Cosx)}/{(1+Cosx)(1-Cosx)}]

=[(Sinx+Sinx.Cosx)/(1-Cos²x)] +[(Tanx-Sinx)/(1-Cos²x)]

=[(Sinx+Sinx.Cosx+Tanx-Sinx)/Sin²x]=Cotx+Secx.Cosecx

₀⁰₀ LHS=RHS

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