sin x/ 1- cosx + tanx /1+ cos x = sec x. cosec. x + cot x
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Answer:
Sinx/(1-Cosx) +Tanx/(1+Cosx)
Step-by-step explanation:
LHS=Sinx/(1-Cosx) +Tanx/(1+Cosx)=[{Sinx.(1+Cosx)}/{(1-Cosx)(1+Cosx)}] +[{Tanx.(1-Cosx)}/{(1+Cosx)(1-Cosx)}]
=[(Sinx+Sinx.Cosx)/(1-Cos²x)] +[(Tanx-Sinx)/(1-Cos²x)]
=[(Sinx+Sinx.Cosx+Tanx-Sinx)/Sin²x]=Cotx+Secx.Cosecx
₀⁰₀ LHS=RHS
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