Question

......
sin(x+9)
If the period of
(I.) is G.I.F)
COS X​

Answer 1

Answer:

Let a line through the origin intersect the unit circle, making an angle of θ with the positive half of the x-axis. The x- and y-coordinates of this point of intersection are equal to cos(θ) and sin(θ), respectively. This definition is consistent with the right-angled triangle definition of sine and cosine when 0° < θ < 90°. Because the length of the hypotenuse of the unit circle is always 1, {\displaystyle \sin(\theta )={\frac {\textrm {opposite}}{\textrm {hypotenuse}}}={\frac {\textrm {opposite}}{1}}={\textrm {opposite}}}{\displaystyle \sin(\theta )={\frac {\textrm {opposite}}{\textrm {hypotenuse}}}={\frac {\textrm {opposite}}{1}}={\textrm {opposite}}}. The length of the opposite side of the triangle is simply the y-coordinate. A similar argument can be made for the cosine function to show that cos(θ) {\displaystyle ={\frac {\textrm {adjacent}}{\textrm {hypotenuse}}}}{\displaystyle ={\frac {\textrm {adjacent}}{\textrm {hypotenuse}}}} when 0° < θ < 90°, even under the new definition using the unit circle. tan(θ) is then defined as {\displaystyle {\frac {\sin(\theta )}{\cos(\theta )}}}{\displaystyle {\frac {\sin(\theta )}{\cos(\theta )}}}, or, equivalently, as the gradient of the line segment.

Using the unit circle definition has the advantage that the angle can take any real argument. This can also be achieved by requiring certain symmetries and that sine be a periodic function.

Answer 2

Answer:

Sorry mate, but i couldn't interpret your question!

Put it in a more detailed but concise form.