Question

sin x cos x dx can you answer me this question please ​

Answer 1

Answer:

$above \: is \: your \: answer.$

Explanation:

@MNF

Answer 2

Answer:

=(Sinx dx).Cosx +(Cosx dx).Sinx [{using product rule}]

=Cosx.Cosx +[(-Sinx).Sinx ].

{{{Since (d/dx of Sinx=Cosx )&(d/dx of Cosx = -Sinx )

=(Cos^2 x -Sin^2 x )

=Cos 2x.