Math, asked by wwwmalvika01, 4 months ago

sin x minus sin 3x upon sin square x minus cos square x​

Answers

Answered by Anonymous
1

Answer:

sinx tan2x

Step-by-step explanation:

sinx - sin3x /(sin²-cos²x)

2*sin(x-3x)*sin(x+3x)2/ (sin²-cos²x)

=2sin(-x)sin2x / -cos2x

=-sinx sin2x/-cos2x

= sinx tan2x

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