Question

sin x + sin y = a and cos x + cos y = b then show that sin (x+y) = 2ab/ a^2+ b^2 and cos ( x+y) = b^2-a^2/ a^2+b^2​

Answer 1

Answer:

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Step-by-step explanation:

sin (x+y) = sinxcosy + cosxsiny

L. H. S = ( a^2 + b^2) / 2ab

put value of a and b

a^2 + b^2 = 2sinxsiny + 2cosxcosy

and 2ab= 2( sinxcosx + sinycosy + sinxcosy + sinycosx)

so devide both

you simplified it you got

Rhs = lhs

Answer 2

Answer:

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