Question

sin(-x) + sinx
[A] 0 [B] –1 [C] 1 [D] 2

Answer 1

Answer:

sin(-x)+ sin(x)

sin(-x)= -sin(x)

putiing value of sin(-x) in above equation

-sin(x)+sin(x)

= 0

Option A i.e 0 is correct

Step-by-step explanation:

hope it helps you

Answer 2

Heya,

$\sin(x)$ is an odd function. That is, $\sin( - x) = - ( \sin(x)$

So, the question is

$\sin( - x) + \sin(x) \\ \\ = > - \sin(x) + \sin(x) \\ = > 0$

Hence, the answer is (A) 0.

Thanks for the question.