Question

sin x tan x/ 1- cos x = 1 + sec x.​

Answer 1

Answer:

sinxtanx/1-cosx

open tanx

sinxsinx/cosx(1-cosx)

sin^2x/cosx(1-cosx)

now open sin^2x

1-cos^2x/cosx(1-cosx)

we know a^2-b^2=(a+b)(a-b)

use it

(1+cosx)(1-cosx)/cosx(1-cosx)

weget

(1+cosx)/cosx

1/cosx+cosx/cosx

secx+1

hope it help

Explanation: