Sin (x-y) cosx-Cos(x-y) Sinx = -siny
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Answer:
to prove sin(x-y)cos x - cos(x-y)sin x = - siny
=> sin(x-y) cos x= sin x cos x cos y - cos² x sin y (1)
Step-by-step explanation:
=>cos (x-y) sin x = cos x sin x cos y + sin² x sin y (2)
1 - 2
=> - cos² x sin y - sin² x sin y
=> - sin y [ cos² x + sin² x ]
=> - sin y [ cos² x + sin² x = 1 ]
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