Question

sin (x + y + sin(x
n(x-y) -​

Answer 1

Step-by-step explanation:

Given sinx=siny

⇒sinx−siny=0

⇒2cos(2x+y)sin(2x−y)=0

⇒cos(2x+y)=0 or sin(2x−y)=0

∴2x+y=(2n+1)2π or 2x−y=nπ,n∈Z

⇒x=(2n+1)π−y or x=2nπ+y

⇒x=(2x+1)π+(−1)2n+1y or x=2nπ+(−1)2ny

Combining these two results, we get

x=nπ+(−1)ny,n∈Z.