Question

sin'x=y then

$0 \leqslant y \ \leqslant \pi$
$- \pi \div 2 \leqslant y \leqslant \pi \div 2$
$0 < y < \pi$
$- \pi2 < y < \pi \div 2$
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Answer 1

THANKS FOR FREE POINTS.........

Answer 2

CAN NOT UNDERSTAND YOUR QUESTION