Question

sin x =y² + 1 then (x, y) =​

Answer 1

Step-by-step explanation:

As −1≤sinθ≤1

⇒0≤sin

2

θ≤1

⇒0≤

2x

x

2

+y

2

+1

≤1

Now from

2xy

x

2

+y

2

+1

≥0⇒x

2

+y

2

+1≥0 ...(1)

And from

2x

x

2

+y

2

+1

≤1⇒x

2

+y

2

+1≤2x⇒(x−1)

2

+y

2

≤0 ...(2)

(1) and (2) only holds when x=1 and y=0

Answer 2

Answer:

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