Math, asked by TheDeficientExplorer, 9 months ago

sin°/1-cos°=1+cos°/sin°=cosec°+cot°​

Answers

Answered by Anonymous
1

Answer:

1.

sin°/1-cos° = 1+cos°/sin°

sin^2 = (1+ cos°) × (1- cos°)

sin^2 = 1^2 - cos^2

sin^2 = sin^2

2.

1+cos°/sin° = cosec°+cot°

1+cos°/sin°= 1/sin° + cos°/sin°

1 + cos°/sin° = cosec° + cot°

Hence, proved.

Hope it helps.

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