sin°/1-cos°=1+cos°/sin°=cosec°+cot°
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here is the correct answer please mark me brainest and give thanks
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Step-by-step explanation:
cosec°+cot° = 1/sin°+cos°/sin°=1+cos°/sin°
sin°/1-cos°= sin°(1+cos°)/(1-cos°)(1+cos°)
=sin°(1+cos°)/1-cos²°
=sin°(1+cos°)/sin²°+cos²°-cos²°
=sin°(1+cos°)/sin²°
=1+cos°/sin°
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