Math, asked by zaivainveer, 8 months ago

sin°/1-cos°=1+cos°/sin°=cosec°+cot°

Answers

Answered by ramsewaksehgon
2

Answer:

here is the correct answer please mark me brainest and give thanks

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Answered by rohitrs0908
0

Answer:

Step-by-step explanation:

cosec°+cot° = 1/sin°+cos°/sin°=1+cos°/sin°

sin°/1-cos°= sin°(1+cos°)/(1-cos°)(1+cos°)

=sin°(1+cos°)/1-cos²°

=sin°(1+cos°)/sin²°+cos²°-cos²°

=sin°(1+cos°)/sin²°

=1+cos°/sin°

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