(sin0+cos0) (1-sin0cos0) can be written as
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Answer:
LHS,
tan 0 + c os 0/1 +s in 0
Now just putting the values of of 0° of respective tan, cos & sin
= 0+1/1 + 0
=1= cos 0 = sec 0 (proved)
we know s ec 0= 1/c os 0 = 1/1=1
Step-by-step explanation:
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