Math, asked by madhukar36, 1 year ago

sin0degree =infinity
proove it

Answers

Answered by VemugantiRahul
2
Sine value is never infinite.
and
Sin 0°= 0

Proof can either be given based on power series method or general method.

1. power series of sinx:
sinx= x - (x³/3!) + (x^5/5!) - (x^7/7!)+…

sub x= 0
sin 0= 0

2. General Explanation:
In right angle triangle, if hypotenuse is rotated towards base, to make its acute angle as 0°.
Then the perpendicular goes on decreasing and finally becomes 0.
But there, Hyp= Base

Sin = Opp/Hyp

Now Find Sin 0:
Opp= 0 & Hyp= 1
sin 0 = 0/1
Sin 0= 0

;)
hope it helps
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madhukar36: proove it
VemugantiRahul: sin 0 = 0
VemugantiRahul: ok
madhukar36: proove that sin0=0
VemugantiRahul: check now
VemugantiRahul: proof added
VemugantiRahul: got it?
Answered by beautiful68
2
※ HELLO BUDDY ※

Q. Sin 0° = ∞

Solution :

→ Since any number multiplied by zero is zero.

→ We get the expression like this 0/0.

→ In multiplication if we multiply any number with 0 we get the value also as Zero.

→ Sin 0° is infinity as this doesn't have any value to it.

→ the graphs of the sine and cosine function and thereby recall that sin0 = 0, cos0 = 1.

→ It is just a finite value between 1 and -1. But, one can't tell the exact value. 

→ So , Sin 0° = 0 .

→ This happens in trigonometry table values.

→ This is my proof !!

★ HOPE U LIKED IT ☺ ★

beautiful68: Guys plz dnt fight
VemugantiRahul: prooved already
VemugantiRahul: just trying to correct him... it is isnt a fight
madhukar36: i am not fighting i am just challenging to sinodegree=0/0
beautiful68: okay he understood plz leave
VemugantiRahul: ok beautiful68... seems he cant get it ...
beautiful68: yes
madhukar36: i am leaving the discussion over this topic it seems that you are not understanding my concepts
beautiful68: please leave dear
beautiful68: I am getting too continuous notifications
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