sin10+sin20+sin30+sin40+sin50+sin60
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answer is zero.
= sin 10+sin20+sin30 + sin40 +...sin180 + sin(360-170)+ ……...+sin(360-40)+sin(360-30)+sin(360-20)+sin360-10)+sin360
sin360-x = - sin x
here all the terms cancled out
so, sin10+sin20+sin30+....+sin360=0
rakesh8495:
solve
karke btavo
answer is zero.
= sin 10+sin20+sin30 + sin40 +...sin180 + sin(360-170)+ ……...+sin(360-40)+sin(360-30)+sin(360-20)+sin360-10)+sin360
sin360-x = - sin x
here all the terms cancled out
so, sin10+sin20+sin30+....+sin360=0
= sin 10+sin20+sin30 + sin40 +...sin180 + sin(360-170)+ ……...+sin(360-40)+sin(360-30)+sin(360-20)+sin360-10)+sin360
sin360-x = - sin x
here all the terms cancled out
so, sin10+sin20+sin30+....+sin360=0
thanks
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Step-by-step explanation:
question is tan^2a+cot^2a = 2 value of a
answer is a = 45°
your first question
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