Question

sin10 sin30 sin50 sin70=1/16​

Answer 1

Answer:

Step-by-step explanation:

we can write the same as

sin10 sin 70 sin 30 sin 50

$\frac{2}{2}$ ( sin 10 sin 70 sin 30 sin 50)

1/2 [ 2 sin 10 sin70 sin 30 sin 50]

1/2[ 2 sin 10 cos 20 sin 30 cos 40]

THE FORMULA OF 2 SIN A COS B = SIN(A+B) + SIN (A-B)

$\frac{2}{2}$ * 1/2 * [ 2 sin 10 cos 20 sin 30 cos 40]

1/2 * 1/2 [ 2 sin 10 cos 20  2 sin 30 cos 40]

1/4 [ sin(30)+sin(-10) * sin (70)  + sin (-10)]

1/4 [ sin 30 - sin 10] * [sin 70-sin 10]

now applying the formula of sin C - sin D,

you will get the answer

thank you

hope it helps you!! :)