Math, asked by srhi, 1 year ago

sin10.sin30.sin50.sin70=1/16

Answers

Answered by Anonymous
2
HEY MATE HERE IS YOUR ANSWER

SIN 10 SIN 30 SIN 50 SIN 70 =( 1/2 )

SIN 10 SIN 50 SIN 70 MULTIPLY AND DIVIDE WITH 2 COS 10 =2

COS 10 SIN 10 SIN 50 SIN 70 / ( 2x2 COS 10 )

( 2SinA COS A = Sin2A ) = SIN 20 SIN 50 SIN 70 / ( 4 COS 10 ) MULTIPLY AND DIVIDE WITH 2 → 2 x Sin 20 SIN 50 SIN ( 90 - 20 ) / ( 2 x 4 Cos 10 )
→2 Sin 20 Cos 20 Sin 50 / 8 Cos 10
→ Sin 40 Sin 50 / 8 Cos 10 ( 2 SinA Cos A = Sin2A )
Ahain multiply and divide with 2. → 2 x Sin 40 Sin ( 90 - 40 ) / 2 x 8 Cis 10. → 2 x Sin 40 Cos 40 / 2 x 8 Cos ( 90 - 80 ) → Sin 80 / 16 Sin 80 = 1/16..

HOPE IT HELPS
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