Question

Sin10.sin50.sin60.sin70=√3/16

Answer 1

Given, sin10.sin50.sin60.sin70 

=sin 60.sin10.sin50.sin70 

= [(√3)/2]sin10sin50sin70 

= [(√3)/2]sin10(cos(-20) - cos120)/2 

= [(√3)/2]sin10(cos20 - cos120)/2 

= [(√3)/2](sin10cos20 - sin10cos120)/2 

= [(√3)/2](sin30 + sin(-10) - 2sin10cos120)/4 

= [(√3)/2](sin30 + sin(-10) + sin10)/4 

= [(√3)/2](1/2)/4 

= (√3)/16 

Answer 2

HERE IS YOUR ANSWER.

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