Sin10×Sin50×Sin60×Sin70=(√3)/16
Answers
Answered by
1
Step-by-step explanation:
Given, sin10.sin50.sin60.sin70
=sin 60.sin10.sin50.sin70
= [(√3)/2]sin10sin50sin70
= [(√3)/2]sin10(cos(-20) - cos120)/2
= [(√3)/2]sin10(cos20 - cos120)/2
= [(√3)/2](sin10cos20 - sin10cos120)/2
= [(√3)/2](sin30 + sin(-10) - 2sin10cos120)/4
= [(√3)/2](sin30 + sin(-10) + sin10)/4
= [(√3)/2](1/2)/4
= (√3)/16
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Answered by
0
Step-by-step explanation:
(√3)/16 is your answer
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