Math, asked by Jessej8250, 1 year ago

Sin10.sin50.sin60.sin70=√3/16 prove it

Answers

Answered by nndubey000
24
sin10.sin50.√3/2.sin70
√3/2.sin10.1/2[2sin50sin70]
√3/4sin10[cos(-20)-cos120]
√3/4.sin10.[cos20-(-1/2)]
√3/8sin10[2cos20+1]
√3/82sin10.cos30+sin10
√3/8sin30+sin(-10)+sin10
√3/8.1/2-sin10+sin10
√3/16. .................... Proved
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