sin10°+sin70-sin40°=?
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Answered by
0
Answer:
Step-by-step explanation:
sin10+sin70-sin40
2sin40cos30-sin40
sin40(2cos30-1)
sin40(root3 -1)
approximately sin 40
Answered by
0
Answer:
sin10 -sin40+sin40
sin x-siny= 2cos (X+y)sin (x+y)
2cos(40+10)sin (40-10)+sin70
2cos50sin30+sin70
sin30=1/2
2cos50*1/2+sin70
cos50+sin70
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