Question

Sin11°19'cos18°41'+cos11°19'sin18°41'=?
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Answer 1

SOLUTION

TO DETERMINE

Sin11°19'cos18°41'+cos11°19'sin18°41'

FORMULA TO BE IMPLEMENTED

We are aware of the Trigonometric formula that

$\sf{}\sin(A + B ) = \sin A \cos B + \cos A \sin B$

EVALUATION

Now

$\sf{} \sin {11}^{ \circ} 19' \: \cos{18}^{ \circ} 41' + \cos {11}^{ \circ} 19' \sin {18}^{ \circ} 41'$

$= \sf{} \sin ({11}^{ \circ} 19' + {18}^{ \circ} 41') \: (using \: above \: formula)$

$= \sf{} \sin {29}^{ \circ} 60'$

$= \sf{} \sin {30}^{ \circ} \: \: ( \because \: {1}^{ \circ} = 60' )$

$= \displaystyle \sf{} \frac{1}{2}$

FINAL ANSWER

$\boxed{ \displaystyle\sf{} \sin {11}^{ \circ} 19' \: \cos{18}^{ \circ} 41' + \cos {11}^{ \circ} 19' \sin {18}^{ \circ} 41' = \frac{1}{2} }$

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LEARN MORE FROM BRAINLY

if cosx+cosy+cosz=0=sinx+siny+sinz

then the possible value of cos(x-y/2)=k

then |2k|=?

https://brainly.in/question/19988900